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Mathematics
Problem
The expression
tan
A
1
−
cot
A
+
cot
A
1
−
tan
A
\frac{\tan A}{1 - \cot A} + \frac{\cot A}{1 - \tan A}
1
−
c
o
t
A
t
a
n
A
+
1
−
t
a
n
A
c
o
t
A
can be written as [2013 JEE Main] a.
sin
A
cos
A
+
1
\sin A \cos A + 1
sin
A
cos
A
+
1
b.
sec
A
csc
A
+
1
\sec A \csc A + 1
sec
A
csc
A
+
1
c.
tan
A
+
cot
A
\tan A + \cot A
tan
A
+
cot
A
d.
sec
A
+
csc
A
\sec A + \csc A
sec
A
+
csc
A
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