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Mathematics
Problem
Given that
sin
3
θ
=
1
\sin 3\theta = 1
sin
3
θ
=
1
with
0
<
θ
<
π
2
0<\theta<\dfrac{\pi}{2}
0
<
θ
<
2
π
, find
sin
θ
\sin\theta
sin
θ
. a)
1
3
\dfrac{1}{3}
3
1
b)
3
2
\dfrac{\sqrt{3}}{2}
2
3
c)
1
2
\dfrac{1}{2}
2
1
d)
1
1
1
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