Problem

Problem

If (x−a)cos⁡θ+ysin⁡θ=a(x - a) \cos \theta + y \sin \theta = a and tan⁡(θ2)−tan⁡(ϕ2)=2b\tan\left(\frac{\theta}{2}\right) - \tan\left(\frac{\phi}{2}\right) = 2b , then a. y2=2ax−(1−b2)x2y^2 = 2ax - (1 - b^2)x^2 b. tan⁡θ2=1x(y+bx)\tan \frac{\theta}{2} = \frac{1}{x}(y + bx) c. y2=2bx−(1−a2)x2y^2 = 2bx - (1 - a^2)x^2 d. tan⁡ϕ2=1x(y−bx)\tan \frac{\phi}{2} = \frac{1}{x}(y - bx)

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