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Chemistry
Chemistry
Problem
The standard potential of the reaction
H
2
O
+
e
−
→
1
2
H
2
+
OH
−
\text{H}_2\text{O} + \text{e}^- \rightarrow \frac{1}{2} \text{H}_2 + \text{OH}^-
H
2
O
+
e
−
→
2
1
H
2
+
OH
−
at 298 K by using
K
w
(
H
2
O
)
=
10
−
14
K_w(\text{H}_2\text{O}) = 10^{-14}
K
w
(
H
2
O
)
=
1
0
−
14
, is: (a)
−
0.826
V
-0.826\text{ V}
−
0.826
V
(b)
0.826
V
0.826\text{ V}
0.826
V
(c)
0
V
0\text{ V}
0
V
(d)
−
0.5
V
-0.5\text{ V}
−
0.5
V
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