Physics

Physics

Problem

If the capacitance of a nanocapacitor is measured in terms of a unit 'u' made by combining the electric charge 'e', Bohr radius 'a0', Planck's constant 'h' and speed of light 'c' then: a. u=e2ha0u = \frac{e^2h}{a_0} b. u=hce2a0u = \frac{hc}{e^2a_0} c. u=e2cha0u = \frac{e^2c}{ha_0} d. u=e2a0hcu = \frac{e^2a_0}{hc}

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