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Mathematics
Mathematics
Problem
Let
f
(
x
)
=
tan
−
1
(
(
x
−
2
)
x
2
+
2
x
+
2
)
f(x) = \tan^{-1}\left(\frac{(x-2)}{x^2+2x+2}\right)
f
(
x
)
=
tan
−
1
(
x
2
+
2
x
+
2
(
x
−
2
)
)
, then
26
f
′
(
1
)
26f'(1)
26
f
′
(
1
)
is
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