Chemistry

Chemistry

Problem

A chemist is studying two structural isomers with molecular formula C2H4O2C_2H_4O_2. • Molecule X is acetic acid, CH3COOHCH_3COOH. • Molecule Y is methyl formate, HCOOCH3HCOOCH_3. Using X-ray diffraction, the chemist obtains the following experimental data: • In molecule X the C–O bond in the hydroxyl group is 133 pm133\,\text{pm}. • In molecule Y the corresponding C–O bond is 143 pm143\,\text{pm}. A compilation of typical single-bond radii predicts a C–O single bond length of 143 pm143\,\text{pm} and a C=O double bond length of 121 pm121\,\text{pm}. a. Part 1: (a) Draw the most important Lewis structure(s) for each molecule, including any significant resonance contributors, and assign formal charges. b. Part 2: (b) For each molecule, identify every C–O bond and state whether resonance would be expected to alter its idealized single- or double-bond character. c. Part 3: (c) Use resonance and formal-charge arguments to explain why the C–O bond length in the hydroxyl group of acetic acid is shorter than the corresponding bond in methyl formate. d. Part 4: (d) Predict which of the two molecules will have the higher average C–O bond dissociation energy and provide a quantitative estimate for that bond energy by interpolating between the tabulated single- and double-bond values. Show your reasoning.

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