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Mathematics
Mathematics
Problem
Show that for
0
<
x
≤
1
0 < x \le 1
0
<
x
≤
1
,
arctan
(
1
−
x
2
x
)
=
arccos
x
.
\arctan\left(\dfrac{\sqrt{1 - x^{2}}}{x}\right)=\arccos x.
arctan
(
x
1
−
x
2
)
=
arccos
x
.
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