Chemistry

Problem

The specific conductivity of a saturated solution of AgCl is

3.40 \times 10^{-6}\text{ ohm}^{-1}\text{ cm}^{-1}

25^\circ\text{C}

. If

\lambda^\circ_{\text{Ag}^+} = 62.3\text{ ohm}^{-1}\text{ cm}^2\text{ mol}^{-1}

and

\lambda^\circ_{\text{Cl}^-} = 67.7\text{ ohm}^{-1}\text{ cm}^2\text{ mol}^{-1}

, the solubility of AgCl at

25^\circ\text{C}

is: (a)

2.6 \times 10^{-5}\text{ M}

(b)

4.5 \times 10^{-3}\text{ M}

(c)

3.6 \times 10^{-5}\text{ M}

(d)

3.6 \times 10^{-3}\text{ M}