Mathematics

Mathematics

Problem

A small factory sells each gadget for ₹150. The total cost (in rupees) of producing xx gadgets is 100x+2000100x + 2000. Let P(x)P(x) denote the profit, where P(x)=R(x)−C(x)P(x)=R(x)-C(x). For what value of xx does the factory break even, that is, P(x)=0P(x)=0? a) 2020 b) 4040 c) 5050 d) 8080

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