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Mathematics
Mathematics
Problem
Show that, for every acute angle
θ
\theta
θ
,
1
−
sin
θ
1
+
sin
θ
=
(
sec
θ
−
tan
θ
)
2
.
\frac{1-\sin \theta}{1+\sin \theta}=\left(\sec \theta-\tan \theta\right)^{2}.
1
+
sin
θ
1
−
sin
θ
=
(
sec
θ
−
tan
θ
)
2
.
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