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Mathematics
Mathematics
Problem
If
x
,
y
,
z
>
0
x, y, z > 0
x
,
y
,
z
>
0
and
x
+
y
+
z
=
1
x + y + z = 1
x
+
y
+
z
=
1
then
x
y
z
(
1
−
x
)
(
1
−
y
)
(
1
−
z
)
\frac{xyz}{(1-x)(1-y)(1-z)}
(
1
−
x
)
(
1
−
y
)
(
1
−
z
)
x
y
z
is necessarily. (a)
≥
8
\ge 8
≥
8
(b)
≤
1
8
\le \frac{1}{8}
≤
8
1
(c) 1 (d) None of these
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