Chemistry

Problem

\Lambda_M

of a solution is

419 \times 10^{-4}\text{ S m}^2\text{mol}^{-1}

for an electrolyte

\text{K}_2\text{SO}_4

300\text{ K}

. The resistance offered by the solution with cell constant

0.88\text{ m}^{-1}

210\text{ ohm}

, the molarity of

\text{K}_2\text{SO}_4

solution is : a.

1 \times 10^{-4}\text{ M}

0.02\text{ M}

0.05\text{ M}

0.03\text{ M}