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Mathematics
Problem
A bijective function
f
:
R
→
R
f:\mathbb R\to\mathbb R
f
:
R
→
R
satisfies
(
g
∘
f
)
(
x
)
=
x
(g\circ f)(x)=x
(
g
∘
f
)
(
x
)
=
x
for every
x
∈
R
x\in\mathbb R
x
∈
R
with some function
g
g
g
. Is this single condition sufficient to conclude that
g
=
f
−
1
g=f^{-1}
g
=
f
−
1
? Give a brief reason.
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