Two identical metal plates are given positive charges Q1 and Q2 (Q2<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
a. (Q1+Q2)/(2C)
b. (Q1+Q2)/C
c. (Q1−Q2)/C
d. (Q1−Q2)/(2C)