Chemistry

Problem

A galvanic cell consists of a magnesium electrode in a

0.15\,\text{M}

^{2+}

solution and a lead electrode in a

1.5\,\text{M}

^{2+}

solution at 298 K. Relevant standard reduction potentials are Pb

^{2+}

+ 2 e

^{-}

→ Pb

E^{\circ}=-0.13\,\text{V}

^{2+}

+ 2 e

^{-}

→ Mg

E^{\circ}=-2.37\,\text{V}

What is the cell potential

E

under the stated conditions? a)

2.30\,\text{V}

2.27\,\text{V}

2.24\,\text{V}

2.21\,\text{V}