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Mathematics
Mathematics
Problem
Let
cos
(
α
+
β
)
=
4
5
\cos(\alpha + \beta) = \frac{4}{5}
cos
(
α
+
β
)
=
5
4
and
sin
(
α
−
β
)
=
5
13
\sin(\alpha - \beta) = \frac{5}{13}
sin
(
α
−
β
)
=
13
5
, where
0
≤
α
,
β
≤
π
4
0 \le \alpha, \beta \le \frac{\pi}{4}
0
≤
α
,
β
≤
4
π
. Then,
tan
2
α
\tan 2\alpha
tan
2
α
is equal to a.
25
16
\frac{25}{16}
16
25
b.
56
33
\frac{56}{33}
33
56
c.
19
12
\frac{19}{12}
12
19
d.
20
7
\frac{20}{7}
7
20
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