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Mathematics
Problem
Show that the area included between the parabolas
y
2
=
4
a
(
x
+
a
)
y^2 = 4a(x+a)
y
2
=
4
a
(
x
+
a
)
and
y
2
=
4
b
(
b
−
x
)
y^2 = 4b(b-x)
y
2
=
4
b
(
b
−
x
)
is
8
3
(
a
+
b
)
a
b
\frac{8}{3}(a+b)\sqrt{ab}
3
8
(
a
+
b
)
ab
.
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