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Mathematics
Mathematics
Problem
Let
R
R
R
be the region that lies
inside both
of the curves
r
=
2
sin
θ
r=2\sin\theta
r
=
2
sin
θ
and
r
=
1
r=1
r
=
1
. What is the exact area of
R
R
R
? a)
4
π
3
−
3
\displaystyle \frac{4\pi}{3}-\sqrt{3}
3
4
π
−
3
b)
2
π
3
−
3
2
\displaystyle \frac{2\pi}{3}-\frac{\sqrt{3}}{2}
3
2
π
−
2
3
c)
π
3
+
2
−
3
\displaystyle \frac{\pi}{3}+2-\sqrt{3}
3
π
+
2
−
3
d)
2
π
3
+
3
2
\displaystyle \frac{2\pi}{3}+\frac{\sqrt{3}}{2}
3
2
π
+
2
3
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