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Physics
Physics
Problem
For a certain series LCR circuit, the current amplitude is maximum at
ω
=
4.0
×
10
3
rad s
−
1
\omega = 4.0\times10^{3}\,\text{rad s}^{-1}
ω
=
4.0
×
1
0
3
rad s
−
1
. The amplitude falls to
I
max
/
2
I_{\max}/\sqrt{2}
I
m
a
x
/
2
at
ω
=
3.6
×
10
3
rad s
−
1
\omega = 3.6\times10^{3}\,\text{rad s}^{-1}
ω
=
3.6
×
1
0
3
rad s
−
1
and
ω
=
4.4
×
10
3
rad s
−
1
\omega = 4.4\times10^{3}\,\text{rad s}^{-1}
ω
=
4.4
×
1
0
3
rad s
−
1
. The quality factor
Q
Q
Q
of the circuit is a)
10
10
10
b)
2.5
2.5
2.5
c)
5
5
5
d)
15.7
15.7
15.7
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