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Mathematics
Problem
The diameter of a virus is given as
1.25
×
10
−
8
m
1.25 \times 10^{-8}\,\text{m}
1.25
×
1
0
−
8
m
. Express this diameter in nanometres (nm) in standard decimal form.
(
1
nm
=
10
−
9
m
)
(1\,\text{nm}=10^{-9}\,\text{m})
(
1
nm
=
1
0
−
9
m
)
a)
125
nm
125\,\text{nm}
125
nm
b)
1.25
nm
1.25\,\text{nm}
1.25
nm
c)
12.5
nm
12.5\,\text{nm}
12.5
nm
d)
0.125
nm
0.125\,\text{nm}
0.125
nm
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