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Mathematics
Mathematics
Problem
Let the polar curve be
r
=
2
+
sin
θ
r=2+\sin\theta
r
=
2
+
sin
θ
. Determine the equation of the tangent line in slope–intercept form at
θ
=
π
6
\theta=\dfrac{\pi}{6}
θ
=
6
π
. a)
y
=
3
3
x
+
25
2
y=3\sqrt{3}\,x+\dfrac{25}{2}
y
=
3
3
x
+
2
25
b)
y
=
−
3
3
x
−
25
2
y=-3\sqrt{3}\,x-\dfrac{25}{2}
y
=
−
3
3
x
−
2
25
c)
y
=
−
3
3
x
+
25
2
y=-3\sqrt{3}\,x+\dfrac{25}{2}
y
=
−
3
3
x
+
2
25
d)
y
=
−
3
3
x
+
25
2
y=-\dfrac{\sqrt{3}}{3}\,x+\dfrac{25}{2}
y
=
−
3
3
x
+
2
25
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