Introduction to Probability · Problem 4.1.51

Conditional Probability — Grinstead & Snell

Mathematics — Probability · conditional-probability-inequality

Problem

Prove that if P(A∣C)≥P(B∣C)andP(A∣C~)≥P(B∣C~),P(A|C) \ge P(B|C) \quad \text{and} \quad P(A|\tilde{C}) \ge P(B|\tilde{C}) , then P(A)≥P(B)P(A) \ge P(B).

Related theory

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