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Mathematics
Problem
Find the particular solution to
d
y
d
x
=
5
(
x
−
2
)
(
x
+
1
)
\displaystyle \frac{dy}{dx}=\frac{5}{(x-2)(x+1)}
d
x
d
y
=
(
x
−
2
)
(
x
+
1
)
5
subject to the initial condition
y
(
3
)
=
0
y(3)=0
y
(
3
)
=
0
.
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