Mathematics

Mathematics

Problem

Show that for 0∘<θ<90∘0^\circ<\theta<90^\circ the following identity holds: a. sin⁡θ+cos⁡θsin⁡θ−cos⁡θ=1+tan⁡θ1−tan⁡θ\dfrac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=\dfrac{1+\tan\theta}{1-\tan\theta}

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