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Mathematics
Mathematics
Problem
Show that for
0
∘
<
θ
<
90
∘
0^\circ<\theta<90^\circ
0
∘
<
θ
<
9
0
∘
the following identity holds: a.
sin
θ
+
cos
θ
sin
θ
−
cos
θ
=
1
+
tan
θ
1
−
tan
θ
\dfrac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=\dfrac{1+\tan\theta}{1-\tan\theta}
sin
θ
−
cos
θ
sin
θ
+
cos
θ
=
1
−
tan
θ
1
+
tan
θ
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