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Mathematics
Problem
The equation of the curve passing through the origin and satisfying the differential equation
(
1
+
x
2
)
d
y
d
x
+
2
x
y
=
4
x
2
is :
[JEE-Main (On line)-2013]
(1 + x^2) \frac{dy}{dx} + 2xy = 4x^2 \text{ is : } \quad \text{[JEE-Main (On line)-2013]}
(
1
+
x
2
)
d
x
d
y
+
2
x
y
=
4
x
2
is :
[JEE-Main (On line)-2013]
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