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Problem
Problem
cos
2
x
−
3
cos
x
+
1
=
1
(
cot
2
x
−
cot
x
)
sin
(
x
−
π
)
\cos 2x - 3 \cos x + 1 = \frac{1}{(\cot 2x - \cot x) \sin(x - \pi)}
cos
2
x
−
3
cos
x
+
1
=
(
c
o
t
2
x
−
c
o
t
x
)
s
i
n
(
x
−
π
)
1
holds, if a.
cos
x
=
0
\cos x = 0
cos
x
=
0
b.
cos
x
=
1
\cos x = 1
cos
x
=
1
c.
cos
x
=
5
2
\cos x = \frac{5}{2}
cos
x
=
2
5
d. for no value of
x
x
x
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