Lebl-Basic-Analysis-I · Problem 4.1.15

The Derivative

Mathematics · lhopital-rule-simple

Problem

Prove the following simple version of L'H\^opital's rule. Suppose f:(a,b)→Rf : (a,b) \to \mathbb{R} and g:(a,b)→Rg : (a,b) \to \mathbb{R} are differentiable functions whose derivatives f′f' and g′g' are continuous functions. Suppose that at c∈(a,b)c \in (a,b), f(c)=0f(c) = 0, g(c)=0g(c) = 0, g′(x)≠0g'(x) \neq 0 for all x∈(a,b)x \in (a,b), and g(x)≠0g(x) \neq 0 whenever x≠cx \neq c. Note that the limit of f′(x)/g′(x)f'(x)/g'(x) as xx goes to cc exists. Show that lim⁡x→cf(x)g(x)=lim⁡x→cf′(x)g′(x).\lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}.

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