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Mathematics
Mathematics
Problem
The value of
∑
n
=
0
50
i
(
2
n
+
1
)
!
\sum_{n=0}^{50} i^{(2n+1)!}
∑
n
=
0
50
i
(
2
n
+
1
)!
(where,
i
=
−
1
i = \sqrt{-1}
i
=
−
1
) is a.
i
i
i
b.
47
−
i
47 - i
47
−
i
c.
48
+
i
48 + i
48
+
i
d. 0
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