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Problems
Define
g
(
x
)
=
{
sin
x
,
0
≤
x
<
π
2
1
,
x
=
π
2
cos
x
,
π
2
<
x
≤
π
g(x)=\begin{cases} \sin x, & 0\le x<\tfrac{\pi}{2}\\ 1, & x=\tfrac{\pi}{2}\\ \cos x, & \tfrac{\pi}{2}<x\le \pi \end{cases}
g
(
x
)
=
⎩
⎨
⎧
sin
x
,
1
,
cos
x
,
0
≤
x
<
2
π
x
=
2
π
2
π
<
x
≤
π
…
Mathematics
Problem
Define
g
(
x
)
=
{
sin
x
,
0
≤
x
<
π
2
1
,
x
=
π
2
cos
x
,
π
2
<
x
≤
π
g(x)=\begin{cases} \sin x, & 0\le x<\tfrac{\pi}{2}\\ 1, & x=\tfrac{\pi}{2}\\ \cos x, & \tfrac{\pi}{2}<x\le \pi \end{cases}
g
(
x
)
=
⎩
⎨
⎧
sin
x
,
1
,
cos
x
,
0
≤
x
<
2
π
x
=
2
π
2
π
<
x
≤
π
Does there exist a value
c
c
c
in
[
0
,
π
]
[0,\pi]
[
0
,
π
]
for which
g
(
c
)
=
0.8
g(c)=0.8
g
(
c
)
=
0.8
? Answer "yes" or "no" and name an interval on which your conclusion is guaranteed.
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