Chemistry

Problem

For a hydrogen-like ion, the energy of the electron in the nth orbit is given by a)

E_n=-\dfrac{13.6\,Z^2}{n}\,\text{eV}

E_n=-\dfrac{13.6\,Z^2}{n^2}\,\text{eV}

E_n=+\dfrac{13.6\,Z^2}{n^2}\,\text{eV}

E_n=-\dfrac{13.6\,Z}{n^2}\,\text{eV}