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Mathematics
Mathematics
Problem
If
∫
0
∞
x
(
1
+
x
)
(
1
+
x
2
)
d
x
=
I
\int_{0}^{\infty} \frac{x}{(1+x)(1+x^2)} dx = I
∫
0
∞
(
1
+
x
)
(
1
+
x
2
)
x
d
x
=
I
then value of
8
I
π
\frac{8I}{\pi}
π
8
I
is :
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