Physics

Physics

Problem

A miner of mass 80 kg80\,\text{kg} works in a mine shaft that reaches a depth of 1 km1\,\text{km} below Earth’s surface. Take RE=6400 kmR_{\rm E}=6400\,\text{km} and g=9.8 m s−2g=9.8\,\text{m\,s}^{-2} at the surface. (a) Calculate the acceleration due to gravity at this depth. (b) Determine the miner’s weight at the depth. (c) Compute the percentage change in his weight relative to the surface value.

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