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Mathematics
Mathematics
Problem
If
(
2
n
+
1
)
θ
=
π
(2^n + 1)\theta = \pi
(
2
n
+
1
)
θ
=
π
, then find the value of
2
n
cos
θ
cos
2
θ
cos
2
2
θ
…
cos
2
n
−
1
θ
2^n \cos \theta \cos 2\theta \cos 2^2 \theta \dots \cos 2^{n-1} \theta
2
n
cos
θ
cos
2
θ
cos
2
2
θ
…
cos
2
n
−
1
θ
.
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