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Problem
Problem
Using mass (
M
M
M
), length (
L
L
L
), time (
T
T
T
) and current (
A
A
A
) as fundamental quantities, the dimension of permeability is a.
[
M
−
1
L
T
−
2
A
]
[M^{-1}LT^{-2}A]
[
M
−
1
L
T
−
2
A
]
b.
[
M
L
−
2
T
−
2
A
−
1
]
[ML^{-2}T^{-2}A^{-1}]
[
M
L
−
2
T
−
2
A
−
1
]
c.
[
M
L
T
−
2
A
−
2
]
[MLT^{-2}A^{-2}]
[
M
L
T
−
2
A
−
2
]
d.
[
M
L
T
−
1
A
−
1
]
[MLT^{-1}A^{-1}]
[
M
L
T
−
1
A
−
1
]
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