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Chemistry
Chemistry
Problem
Calculate mass no., atomic no. and group in the periodic table for RaC in the following change.
88
Ra
226
→
−
α
Rn
→
−
α
RaA
→
−
β
RaB
→
−
α
RaC
{}_{88}\text{Ra}^{226} \xrightarrow{-\alpha} \text{Rn} \xrightarrow{-\alpha} \text{RaA} \xrightarrow{-\beta} \text{RaB} \xrightarrow{-\alpha} \text{RaC}
88
Ra
226
−
α
Rn
−
α
RaA
−
β
RaB
−
α
RaC
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