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Mathematics
Mathematics
Problem
Let
f
(
x
)
=
e
x
2
tan
3
x
f(x)=\dfrac{e^{x^{2}}}{\tan 3x}
f
(
x
)
=
tan
3
x
e
x
2
. Evaluate
f
′
(
x
)
f'(x)
f
′
(
x
)
at
x
=
π
4
x=\dfrac{\pi}{4}
x
=
4
π
. a)
(
π
2
−
6
)
e
π
2
/
16
\left(\dfrac{\pi}{2}-6\right)e^{\pi^{2}/16}
(
2
π
−
6
)
e
π
2
/16
b)
−
(
π
2
+
6
)
e
π
2
/
16
-\left(\dfrac{\pi}{2}+6\right)e^{\pi^{2}/16}
−
(
2
π
+
6
)
e
π
2
/16
c)
(
−
π
2
+
6
)
e
π
2
/
16
\left(-\dfrac{\pi}{2}+6\right)e^{\pi^{2}/16}
(
−
2
π
+
6
)
e
π
2
/16
d)
(
π
2
+
6
)
e
π
2
/
16
\left(\dfrac{\pi}{2}+6\right)e^{\pi^{2}/16}
(
2
π
+
6
)
e
π
2
/16
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