Mathematics

Mathematics

Problem

Let ABCABC be a right triangle with length of side AB=3AB = 3 and hypotenuse AC=5AC = 5 . If DD is a point on BCBC such that BDDC=ABAC\frac{BD}{DC} = \frac{AB}{AC} , then ADAD is equal to a. 433\frac{4\sqrt{3}}{3} b. 352\frac{3\sqrt{5}}{2} c. 453\frac{4\sqrt{5}}{3} d. 534\frac{5\sqrt{3}}{4}

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