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Mathematics
Mathematics
Problem
If
3
tan
2
θ
=
3
\sqrt{3} \tan 2\theta = 3
3
tan
2
θ
=
3
and
0
∘
<
θ
≤
90
∘
0^\circ < \theta \le 90^\circ
0
∘
<
θ
≤
9
0
∘
; find the value of
3
3
cos
θ
+
2
sin
θ
−
6
tan
2
θ
3\sqrt{3} \cos \theta + 2\sin \theta - 6 \tan^2 \theta
3
3
cos
θ
+
2
sin
θ
−
6
tan
2
θ
.
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