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Mathematics
Mathematics
Problem
If
sin
θ
=
3
5
\sin \theta = \dfrac{3}{5}
sin
θ
=
5
3
and
θ
\theta
θ
lies in the second quadrant, find
cos
θ
\cos \theta
cos
θ
. a)
−
16
25
-\dfrac{16}{25}
−
25
16
b)
4
5
\dfrac{4}{5}
5
4
c)
−
4
5
-\dfrac{4}{5}
−
5
4
d)
−
3
5
-\dfrac{3}{5}
−
5
3
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