Physics

Problem

At the same point

(P,V)

on a

P\!

–

\!V

diagram for an ideal gas, how does the slope

\left|\dfrac{dP}{dV}\right|

of the adiabatic curve compare with that of the isothermal curve? a)

\left|\dfrac{dP}{dV}\right|_{\text{adiabatic}}=\gamma\,\left|\dfrac{dP}{dV}\right|_{\text{isothermal}}\;(\gamma>1)

\left|\dfrac{dP}{dV}\right|_{\text{adiabatic}}=\left|\dfrac{dP}{dV}\right|_{\text{isothermal}}

\left|\dfrac{dP}{dV}\right|_{\text{adiabatic}}=\dfrac{1}{\gamma}\,\left|\dfrac{dP}{dV}\right|_{\text{isothermal}}\;(\gamma>1)

\left|\dfrac{dP}{dV}\right|_{\text{adiabatic}}=\gamma^{2}\,\left|\dfrac{dP}{dV}\right|_{\text{isothermal}}