Consider the nth-order homogeneous linear differential equation
andtndnx+an−1dtn−1dn−1x+⋯+a1dtdx+a0x=0.
Show that the solutions take the form of x(t)=Aierit, where the ri depend on the aj coefficients. Hint: If the (d/dt) derivatives were replaced by the letter z, then we would have an nth-order polynomial in z, which we know can be factored, by the fundamental theorem of algebra. (You can assume that the roots of this polynomial are distinct. Things are a little more complicated if there are double roots; this is discussed in the solution.)