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Mathematics
Problem
The number of common tangents to the circles
x
2
+
y
2
−
4
x
−
6
y
−
12
=
0
x^2 + y^2 - 4x - 6y - 12 = 0
x
2
+
y
2
−
4
x
−
6
y
−
12
=
0
and
x
2
+
y
2
+
6
x
+
18
y
+
26
=
0
x^2 + y^2 + 6x + 18y + 26 = 0
x
2
+
y
2
+
6
x
+
18
y
+
26
=
0
is: [JEE(Main)-2015] (1) 1 (2) 2 (3) 3 (4) 4
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