Physics

Physics

Problem

In a draining experiment, the depth of water above a small exit hole decreases from 0.40 m0.40\,\text{m} to 0.10 m0.10\,\text{m}. Neglecting viscosity, which statement best describes how the instantaneous mass flow rate m˙\dot m through the hole changes over this interval? a) m˙\dot m becomes one–quarter its original value because exit speed is directly proportional to depth. b) m˙\dot m doubles because the pressure difference between the surface and the hole increases as the tank empties. c) m˙\dot m becomes one–half its original value because exit speed depends on the square root of depth. d) m˙\dot m remains constant because the density of the fluid does not change.

Browse the problem library