Mathematics

Mathematics

Problem

Let y=y(x)y = y(x) be the solution of the differential equation dydx=4y3+2yx23xy2+x3\frac{dy}{dx} = \frac{4y^3 + 2yx^2}{3xy^2 + x^3}, y(1)=1y(1) = 1. If for some n∈Nn \in \mathbb{N}, y(2)∈[n−1,n)y(2) \in [n-1, n), then nn is equal to ______ [JEE MAINS - ONLINE - 2022]

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