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Mathematics
Mathematics
Problem
Let
f
(
x
)
=
p
x
−
1
x
+
1
f(x)=\dfrac{px-1}{x+1}
f
(
x
)
=
x
+
1
p
x
−
1
(where
x
≠
−
1
x\ne -1
x
=
−
1
) and
g
(
x
)
=
1
x
g(x)=\dfrac{1}{x}
g
(
x
)
=
x
1
(where
x
≠
0
x\ne 0
x
=
0
). Determine the value of
p
p
p
for which
(
g
∘
f
)
(
x
)
=
f
(
x
)
(g\circ f)(x)=f(x)
(
g
∘
f
)
(
x
)
=
f
(
x
)
for every
x
x
x
in the common domain.
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