Chemistry

Problem

The rate of reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be: (

R = 8.314 \text{ JK}^{-1} \text{ mol}^{-1}

and

\log 2 = 0.301

) [JEE Mains-2013] (1)

53.6 \text{ kJ mol}^{-1}

(2)

48.6 \text{ kJ mol}^{-1}

(3)

58.5 \text{ kJ mol}^{-1}

(4)

60.5 \text{ kJ mol}^{-1}