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Mathematics
Problem
Find the point(s) on the circle
x
2
+
y
2
=
25
x^{2}+y^{2}=25
x
2
+
y
2
=
25
at which the tangent is horizontal. a)
(
5
,
0
)
(5,0)
(
5
,
0
)
and
(
−
5
,
0
)
(-5,0)
(
−
5
,
0
)
b)
(
0
,
5
)
(0,5)
(
0
,
5
)
and
(
0
,
−
5
)
(0,-5)
(
0
,
−
5
)
c)
(
5
2
,
−
5
2
)
\left(\dfrac{5}{\sqrt{2}},-\dfrac{5}{\sqrt{2}}\right)
(
2
5
,
−
2
5
)
and
(
−
5
2
,
5
2
)
\left(-\dfrac{5}{\sqrt{2}},\dfrac{5}{\sqrt{2}}\right)
(
−
2
5
,
2
5
)
d)
(
3
,
4
)
(3,4)
(
3
,
4
)
and
(
−
3
,
−
4
)
(-3,-4)
(
−
3
,
−
4
)
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