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Mathematics
Problem
The function
f
(
x
)
=
∣
x
+
2
∣
tan
−
1
(
x
+
2
)
f(x) = \frac{|x+2|}{\tan^{-1}(x+2)}
f
(
x
)
=
t
a
n
−
1
(
x
+
2
)
∣
x
+
2∣
is continuous for a.
x
∈
R
x \in R
x
∈
R
b.
x
∈
R
−
{
0
}
x \in R - \{0\}
x
∈
R
−
{
0
}
c.
x
∈
R
−
{
−
2
}
x \in R - \{-2\}
x
∈
R
−
{
−
2
}
d. None of these
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