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Mathematics
Mathematics
Problem
Which function is continuous on
R
\mathbb{R}
R
but fails to be differentiable at
x
=
2
x=2
x
=
2
specifically because the tangent line is vertical at that point? a)
g
(
x
)
=
∣
x
−
2
∣
g(x)=|x-2|
g
(
x
)
=
∣
x
−
2∣
b)
g
(
x
)
=
1
x
−
2
g(x)=\dfrac{1}{x-2}
g
(
x
)
=
x
−
2
1
c)
g
(
x
)
=
(
x
−
2
)
1
/
3
g(x)=(x-2)^{1/3}
g
(
x
)
=
(
x
−
2
)
1/3
d)
g
(
x
)
=
(
x
−
2
)
2
/
3
g(x)=(x-2)^{2/3}
g
(
x
)
=
(
x
−
2
)
2/3
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